Example/Program Interface Uniforms In Blocks
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Iteration over all uniforms within each uniform block.
GLint numBlocks = 0;
glGetProgramInterfaceiv(prog, GL_UNIFORM_BLOCK, GL_ACTIVE_RESOURCES, &numBlocks);
const GLenum blockProperties[1] = {GL_NUM_ACTIVE_VARIABLES};
const GLenum activeUnifProp[1] = {GL_ACTIVE_VARIABLES};
const GLenum unifProperties[3] = {GL_NAME_LENGTH, GL_TYPE, GL_LOCATION};
for(int blockIx = 0; blockIx < numBlocks; ++blockIx)
{
GLint numActiveUnifs = 0;
glGetProgramResourceiv(prog, GL_UNIFORM_BLOCK, blockIx, 1, blockProperties, 1, NULL, &numActiveUnifs);
if(!numActiveUnifs)
continue;
std::vector<GLint> blockUnifs(numActiveUnifs);
glGetProgramResourceiv(prog, GL_UNIFORM_BLOCK, blockIx, 1, activeUnifProp, numActiveUnifs, NULL, &blockUnifs[0]);
for(int unifIx = 0; unifIx < numActiveUnifs; ++unifIx)
{
GLint values[3];
glGetProgramResourceiv(prog, GL_UNIFORM, blockUnifs[unifIx], 3, unifProperties, 3, NULL, values);
// Get the name. Must use a std::vector rather than a std::string for C++03 standards issues.
// C++11 would let you use a std::string directly.
std::vector<char> nameData(values[0]);
glGetProgramResourceName(prog, GL_UNIFORM, blockUnifs[unifIx], nameData.size(), NULL, &nameData[0]);
std::string name(nameData.begin(), nameData.end() - 1);
}
}