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Type: Posts; User: swillits

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    It is imperative that no work item starts "work"...

    It is imperative that no work item starts "work" until result has been initialized—because they all share the result variable through atomic updates—and the only way to guarantee that is with a...
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    Initializing __local variables

    In my kernel I'm processing NxN chunks of an image in a buffer. Each chunk will produce a single result so each work group is a single chunk and each work item within the group modifies a single...
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